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Motor Current Calculator

Calculate Smarter. Work Faster.

Free motor full load current (FLA/FLC) calculator — enter motor kW or HP, any supply voltage up to 1000 V, and power factor to instantly get amps for single-phase or three-phase motors, plus apparent power (kVA) and a planning reference current.

Motor Details

Fill in the motor's rated power, supply, and performance figures below.

Supply Type
Power Unit
Common Voltages
Single: I = P ÷ (V × PF × η) Three: I = P ÷ (√3 × V × PF × η) 1 mechanical HP = 746 W
Estimated Full Load Current
— A

Estimated running current at rated output — verify against the motor nameplate

Power (kW)
— kW
Power (HP)
— HP
Apparent Power
— kVA
Input Power Drawn
— kW
Planning Reference Current
— A
Formula Used

Enter your values and hit calculate to see the full breakdown.

Protection Sizing Note

Protection sizing is not derived from this planning reference current. Use the motor nameplate FLC and applicable local electrical code to select conductor, overload, and branch-circuit overcurrent protection — starting current must also be considered.

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Created by Umasankar Maity — B.Tech in Electrical Engineering, with 11+ years of industrial maintenance experience.

Reviewed by the ElectroMechCalc editorial team.

Last reviewed: August 2026  |  Method: Generic current calculation using the standard three-phase power relationship P = √3 × V × I × PF, with motor efficiency applied when converting rated mechanical output to electrical input. This is a universal physics relationship, not a code-specific sizing procedure — codes such as IEC, IEEE, BIS, and NEC may prescribe their own FLA tables and load calculation rules, which are not automatically applied here. For code-compliant design, use the motor nameplate FLA or the applicable requirements of the governing electrical standard.

How it works

Understanding Motor Full Load Current

This motor FLA/FLC calculator works as an HP to Amps calculator, a kW to Amps calculator, and a 3-phase or single-phase motor current calculator in one tool, at any supply voltage. Motor FLC formula (three-phase): I = (kW × 1000) ÷ (1.732 × V × PF × Efficiency) — for example, a 15 kW motor at 415 V, PF 0.85, 90% efficiency draws roughly 27.3 A. Full Load Current (FLC), also called Full Load Amps (FLA), is the steady-state current a motor draws from the supply when running at its rated output power. FLC is an important reference value for motor-circuit design, but conductor ampacity, overload protection, contactor rating, and branch-circuit short-circuit/ground-fault protection are each determined by their own distinct rules — not simply FLC plus a fixed allowance; undersize any of these against the real FLC and the motor either nuisance-trips or, worse, overheats the wiring. Motor nameplates usually list a rated FLC, but this calculator lets you verify or estimate it using the standard three-phase power relationship P = √3 × V × I × PF, with motor efficiency applied when converting rated mechanical output to electrical input.

For a single-phase motor, the relationship between electrical input power and current is I = P ÷ (V × PF × η), where P is the rated shaft power converted to watts, V is the supply voltage, PF is the power factor, and η is the motor's efficiency as a decimal. Efficiency is included because the motor's electrical input power is always higher than its rated mechanical output power — a 10 kW motor at 90% efficiency actually draws about 11.1 kW of electrical power to deliver that 10 kW at the shaft.

For a three-phase motor, the same relationship gains a √3 (≈1.732) term to account for the phase geometry of a balanced three-phase system: I = P ÷ (√3 × V × PF × η). If the motor's power is rated in horsepower rather than kilowatts, the calculator first converts it using 1 mechanical HP = 746 W before applying either formula.

Once FLC is known, this calculator also estimates the apparent power (kVA) the supply must deliver, which is simply the product of voltage, current, and the appropriate phase factor divided by power factor, and gives a planning reference current with an adjustable planning headroom added on top of FLC as a general allowance. The headroom used by this calculator is a simplified planning estimate only, not a code-based conductor, overload, fuse, or breaker sizing factor. Actual conductor, overload, and overcurrent protection sizing must follow the applicable local electrical code, motor nameplate data, manufacturer requirements, and installation conditions — cable ampacity, contactor AC-3 rating, thermal overload setting, and branch-circuit overcurrent protection are each sized by their own distinct rule, related to FLC but not all governed by the same single allowance. This calculator does not select a cable, overload, fuse, or breaker size — use the motor nameplate FLC and the applicable code for that step.

As always, treat this as an engineering estimate rather than a substitute for the motor's actual nameplate FLC, which accounts for the specific winding design and test data of that motor. Always cross-check the final cable, breaker, and overload settings against the manufacturer's nameplate and applicable local electrical code before commissioning.

Why FLC Is the Starting Point for Every Downstream Component

Full Load Current is the anchor figure for an entire chain of downstream decisions on a motor circuit. The conductor feeding the motor must have sufficient ampacity under the applicable installation conditions and code requirements — factors such as installation method, ambient temperature, grouping, voltage drop, and insulation rating all play into the final cable selection (see the Cable Size Calculator for that step). The contactor must be rated for FLC under its AC-3 duty classification, which accounts for the make/break duty of switching an inductive motor load rather than a simple resistive one. The thermal overload relay is set according to the motor's nameplate current, the relay's class/type, and the applicable code or manufacturer instructions, so it protects the motor winding from sustained overload without nuisance-tripping on normal load variation. Branch-circuit short-circuit/ground-fault protection is selected according to the applicable code and must accommodate the motor's permitted starting current without nuisance tripping — for a direct-on-line start this inrush is typically 5 to 8 times FLC, though the exact device rating depends on the code, starting method, and equipment used. Getting FLC right, whether from the nameplate or estimated here, is therefore the first and most consequential step in the whole selection chain.

Starting Current vs Full Load Current

It's easy to confuse FLC with starting (inrush) current, but they describe two very different moments in a motor's operation. FLC is the steady-state current drawn once the motor has reached full rated speed under full rated load — this is the number used for cable, contactor, and overload sizing. Starting current, by contrast, is the much larger current an induction motor draws for a fraction of a second (or a few seconds for larger motors) while it accelerates from standstill, because the rotor initially looks almost like a short-circuited transformer secondary to the supply. For a motor started direct-on-line (DOL), this inrush is typically 5–8× FLC; for a star-delta starter it drops to roughly 2–3× FLC; and for a soft starter or VFD it can be limited to as little as 1.5–2× FLC or less. This is why breakers and fuses protecting motor circuits use a "motor rated" or time-delay characteristic rather than an instantaneous trip at FLC — they need to ride through the brief starting surge without tripping, while still protecting against a genuine sustained overload.

How to Use This Motor Current Calculator

  1. Select the phase type — single phase for smaller domestic/workshop motors, three phase for most industrial and commercial applications.
  2. Enter the motor's rated power in kW or HP, whichever matches the nameplate, along with the supply voltage.
  3. Enter the power factor and efficiency from the nameplate if available; if not, 0.85 PF and 88–92% efficiency are reasonable estimates for a typical general-purpose induction motor in this size range.
  4. Click Calculate to see the estimated FLC, apparent power (kVA), and a planning reference current with headroom applied.

Common Mistakes in Motor Current Estimation

  • Forgetting to divide by efficiency. Using rated shaft power directly as electrical input power understates FLC, sometimes by 10% or more.
  • Assuming a flat power factor across all motor sizes. Power factor varies with motor loading and size — small motors and lightly loaded motors often run at a lower PF than their nameplate full-load figure.
  • Sizing the breaker directly at FLC with no headroom. This risks nuisance tripping during normal starting and load fluctuation; an adequate design allowance — sized per the applicable local code and starter type, not a fixed percentage — helps avoid it.
  • Confusing single-phase and three-phase formulas. Missing the √3 term on a three-phase calculation, or wrongly applying it to a single-phase motor, produces an FLC that's off by a factor of roughly 1.73.

Typical Full Load Current Reference (415V, 3-Phase, 0.85 PF)

The table below gives approximate FLC values for common motor sizes as a quick sanity check — always confirm against the actual motor nameplate for final design.

Motor RatingApprox. FLC (A)
5 HP (3.7 kW)6.7 A
10 HP (7.5 kW)13.6 A
20 HP (15 kW)27.3 A
30 HP (22 kW)40.0 A
50 HP (37 kW)67.3 A
100 HP (75 kW)136.4 A

Figures are computed with this calculator's own formula at PF 0.85 and 90% efficiency, for a like-for-like comparison. Actual FLC varies by manufacturer, motor design, and duty class — always confirm against the nameplate.

Illustrative Motor Current Examples by Region

These worked examples show typical motor voltages and full-load current across different supply systems, calculated with this tool's own formula at PF 0.85 and 90% efficiency (enter your motor's actual PF/efficiency for a precise result).

ExampleMotor RatingSupplyFLC (A)
USA10 HP460V, 3-phase≈12.2 A
Canada20 HP600V, 3-phase≈18.8 A
UK / Europe15 kW400V, 3-phase≈28.3 A
Australia11 kW400V, 3-phase≈20.8 A
UAE / Saudi Arabia30 kW400V, 3-phase≈56.6 A
India15 kW415V, 3-phase≈27.3 A

USA NEC & Canada CSA Motor FLA Guidance

In the USA, for installations governed by the National Electrical Code, motor-circuit calculations commonly use the applicable NEC full-load-current tables (commonly Table 430.248 for single-phase and Table 430.250 for three-phase motors) together with the specific requirements of Article 430 — these tabulated values may differ from a direct P÷(√3×V×PF×η) calculation, since they're standardized per NEC edition rather than computed from a specific motor's own PF and efficiency. In Canada, the CSA C22.1 Electrical Code contains motor-current and motor-circuit requirements that should be applied according to the applicable edition and installation. This calculator gives an engineering estimate useful for planning and cross-checking; for NEC/CSA-compliant circuit design, use the code's own published FLA table for the applicable edition, or the motor nameplate FLA, rather than this calculated figure alone.

Starting Methods

How Starting Method Affects Inrush Current

The full-load current calculated here is the motor's steady-state running current — but at the moment of starting, an induction motor briefly draws far more current than this, since it behaves electrically like a short-circuited transformer until it builds up rotational speed. How much more depends heavily on the starting method used:

Starting Method Typical Inrush Starting Torque
Direct-On-Line (DOL)5–8× FLAFull (100%)
Star-DeltaTypically ~2–3× FLA at the supply, depending on motor and system conditions~33% of DOL
Auto-transformer1.7–4× FLA (tap-dependent)Tap-dependent
Soft starterCommonly configurable ~2–4× FLA, depending on current-limit setting, motor and loadAdjustable, smooth ramp
VFD (Variable Frequency Drive)Typically ~1–1.5× FLA with properly configured drive controlDepends on VFD control mode, motor, and load

DOL starting is the simplest and cheapest but imposes the highest inrush and mechanical shock — suitable for small motors where the supply can absorb the surge without disturbing other equipment or tripping upstream protection. As motor size increases, or where the supply is weak, star-delta, soft starters, or VFDs become worth the added cost specifically to tame this inrush current, protect mechanical components (belts, couplings, driven equipment) from starting shock, and avoid voltage dips that can affect other loads on the same supply. This is also why branch-circuit short-circuit/ground-fault protection for a motor circuit is selected according to the applicable code rather than at FLA — it must accommodate the motor's permitted starting current without nuisance tripping, while a separate thermal overload relay, set close to FLA per the applicable code and manufacturer instructions, handles protection against a sustained running overload.

FAQ

Frequently Asked Questions

Content last reviewed: August 2026

Should I use the calculated current or the motor's nameplate FLC? +

Always prefer the nameplate FLC when it's available, since it reflects the actual tested performance of that specific motor design. Use this calculator to estimate FLC when the nameplate is missing, to cross-check a suspicious nameplate value, or when sizing a system before a specific motor model has been chosen.

Why does a three-phase motor draw less current than a single-phase motor of the same power? +

The √3 (≈1.732) factor in the three-phase formula means the same power is delivered using less current per line compared to a single-phase motor at the same voltage, since three-phase power is spread across three conductors instead of two. This is one reason three-phase supply is preferred for larger motors — it allows smaller cable and switchgear for the same power.

Why is efficiency used to calculate current, since current relates to input power? +

A motor's nameplate power rating is its mechanical output (shaft) power, not the electrical power it draws from the supply. Since some input energy is always lost to winding resistance, friction, and core losses, the actual electrical input power is higher than the rated output — dividing by efficiency converts the rated output power to the real electrical input power used in the current formula.

Why add headroom on top of the calculated FLC for planning a conductor and overcurrent device? +

Motors draw a brief inrush/starting current well above FLC, and real-world loads fluctuate slightly above rated conditions. This calculator applies an adjustable planning headroom on top of FLC to allow for this. The headroom used is a simplified planning estimate only — the exact allowance required, and how it applies to conductor, overload, and overcurrent protection sizing, depends on the applicable local electrical code, motor nameplate data, manufacturer requirements, and starting method.

Does power factor correction change the motor's FLC? +

Power factor correction capacitors reduce the reactive current drawn from the supply upstream of the correction point, lowering the total line current and apparent power (kVA) seen by the utility, but they don't change the current the motor itself draws internally at its own terminals. Use the APFC Capacitor Calculator to size correction capacitors for a given load.

What is the full-load current of a 3-phase motor? +

It depends mainly on supply voltage plus the motor's power, efficiency, and power factor. As a rough rule of thumb at ~0.85 PF, a 3-phase motor draws roughly 1.5–1.8 A per kW at 400V/415V, but proportionally less at higher voltages like 460V or 600V used in North America — for example, a 15 kW motor draws roughly 27–28 A at 400V/415V under these assumptions, while at 460V a separate 10 HP motor draws roughly 12 A under the same assumptions. See the examples table above for more voltages, or enter your exact motor rating in the calculator for a precise figure.

Why does a motor draw so much more current when starting than when running? +

At standstill, an induction motor's rotor behaves like a short-circuited transformer winding, offering very low impedance until it builds up speed and back-EMF. This is why starting (inrush) current is typically 5–8× the running full-load current for a Direct-On-Line start (the exact figure depends on motor design and system conditions), and why reduced-voltage starting methods (star-delta, soft starter, VFD) exist specifically to limit this surge.

Should I size the breaker for FLA or for starting inrush current? +

Neither alone — a motor circuit needs both, and they work differently. Running overload protection is based around the motor's FLC/nameplate current and the applicable overload rules, typically set close to FLA. Branch-circuit short-circuit/ground-fault protection is determined separately, and must tolerate the motor's permitted starting current (which can be several times FLA for a DOL start) without nuisance tripping — this is why motor circuits use breakers or fuses with a motor-rated or time-delay characteristic rather than an instantaneous trip at FLA. The exact device type and settings depend on the applicable local code and the starting method used.

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