Heat Exchanger Duty Calculator
Calculate Smarter. Work Faster.
Heat duty from mass flow rate, specific heat and temperature change — plus optional required heat transfer area from U and LMTD.
Heat Duty Inputs
Heat exchanger duty and area, explained
Heat exchanger duty is the rate of heat energy that must be transferred from one fluid stream to another to achieve a required temperature change. For a fluid with no phase change, this is given by the sensible heat equation:
Q = ṁ × Cp × ΔT
Here, ṁ is the mass flow rate of the fluid being heated or cooled, Cp is its specific heat capacity (how much energy it takes to raise 1 kg of the fluid by 1°C), and ΔT is the temperature change it undergoes across the exchanger. With mass flow in kg/s, Cp in kJ/kg·K, and ΔT in °C, the result comes out directly in kW — the standard unit heat exchanger duty is specified in.
This duty figure is the starting point for sizing the exchanger, but it doesn't by itself tell you how large the exchanger needs to be — that depends on how efficiently heat crosses from the hot side to the cold side, which is where the log mean temperature difference (LMTD) and overall heat transfer coefficient (U) come in.
Q = U × A × LMTD
LMTD accounts for the fact that the temperature difference between the two fluids is not constant along the length of the exchanger — it's largest at one end and smallest at the other. For counter-current flow (the two fluids moving in opposite directions, generally the more efficient and more common industrial arrangement), LMTD is calculated from the temperature differences at each end of the exchanger, ΔT₁ and ΔT₂:
LMTD = (ΔT₁ − ΔT₂) / ln(ΔT₁/ΔT₂)
Once Q and LMTD are known, and an estimate of the overall heat transfer coefficient U is available (which depends on the fluids involved, the exchanger type, and the materials used — see the reference table below), the required heat transfer area follows directly by rearranging Q = U × A × LMTD to solve for A. This gives a first-pass estimate of exchanger size, which a detailed thermal design would refine further with fouling factors, correction factors for multi-pass or cross-flow arrangements, and pressure-drop checks.
Worked Example
Water is heated from 25°C to 60°C at 5000 kg/hr, using hot process fluid entering at 95°C and leaving at 70°C in a counter-current shell-and-tube exchanger with U = 800 W/m²·K.
- ṁ = 5000/3600 = 1.389 kg/s, Cp = 4.18 kJ/kg·K, ΔT = 35°C
- Q = 1.389 × 4.18 × 35 = 203.2 kW
- Counter-current: ΔT₁ = 95−60 = 35°C (hot inlet vs cold outlet); ΔT₂ = 70−25 = 45°C (hot outlet vs cold inlet)
- LMTD = (35−45) / ln(35/45) = −10 / −0.2513 = 39.79°C
- Area = Q / (U × LMTD) = 203,200 / (800 × 39.79) = 6.38 m²
This calculator covers sensible (no phase change) heat duty and a simplified counter-current LMTD area estimate; condensing/boiling duty, multi-pass correction factors, and fouling allowances need a full thermal design rather than this simplified tool.
Typical overall heat transfer coefficients (U)
| Service | Typical U (W/m²·K) |
|---|---|
| Water to water | 800 – 1,500 |
| Water to light oil | 300 – 900 |
| Water to heavy oil / viscous fluid | 50 – 300 |
| Steam to water | 1,500 – 4,000 |
| Air to water (finned tube) | 25 – 60 |
| Ammonia condenser (refrigerant to water) | 800 – 1,400 |
These ranges are wide because U depends heavily on fluid velocity, tube material and wall thickness, surface fouling, and exchanger geometry — use the manufacturer's design value or a detailed film-coefficient calculation for final sizing, and treat this table as a first-pass estimating guide only.
Common mistakes when sizing a heat exchanger
1. Using an arithmetic mean temperature difference instead of LMTD. Simply averaging the hot and cold temperature differences at the two ends overstates the effective driving temperature difference whenever the two end-differences are far apart, which understates the required area.
2. Mixing up counter-current and parallel-flow ΔT₁/ΔT₂ pairing. The two flow arrangements pair the hot and cold stream temperatures differently at each end — using the counter-current pairing for a parallel-flow exchanger (or vice versa) gives a wrong LMTD and therefore a wrong area.
3. Forgetting units on Cp. Specific heat is sometimes quoted in kJ/kg·K and sometimes in kcal/kg°C — mixing the two without converting (1 kcal/kg°C = 4.186 kJ/kg·K) throws off the duty calculation by that same factor.
4. Using a single-phase U value for a condensing or boiling duty. Phase-change heat transfer (condensation, boiling) has very different, usually much higher, heat transfer coefficients than sensible (no phase change) heating or cooling — and phase-change duty itself uses latent heat, not Q = mCpΔT, so this calculator's duty formula does not apply to it directly.
5. Ignoring fouling allowance. Real exchangers accumulate scale, deposits, or biological fouling over time, which reduces effective U below its clean-surface value — detailed designs include a fouling factor; a first-pass estimate using clean U alone will undersize the exchanger for long-term service.
6. Applying the single-pass LMTD formula directly to a multi-pass shell-and-tube exchanger. Real multi-pass and cross-flow exchangers need an LMTD correction factor (F) less than 1, since their flow pattern is not purely counter-current — skipping this factor underestimates the required area for anything other than a true single-pass counter-current design.
Frequently Asked Questions
Straight answers on heat duty, LMTD, and heat transfer area.
What is the formula for heat exchanger duty?+
Q equals mass flow rate times specific heat times temperature change, Q = m dot times Cp times Delta T, for sensible heating or cooling with no phase change. With flow in kg per second, Cp in kJ per kg-Kelvin, and Delta T in degrees Celsius, the result comes out directly in kilowatts.
What is LMTD and why not just average the two end temperature differences?+
LMTD, the log mean temperature difference, correctly accounts for the fact that the temperature gap between hot and cold streams changes non-linearly along the exchanger length. A simple arithmetic average overstates the true driving force whenever the two end-differences are noticeably different, which would understate the required heat transfer area.
What's the difference between counter-current and parallel flow arrangement?+
In counter-current flow, the hot and cold fluids move in opposite directions through the exchanger, which generally gives a higher LMTD and therefore requires less area for the same duty. In parallel (co-current) flow, both fluids move the same direction, which is less thermally efficient but sometimes preferred for reasons like limiting the maximum wall temperature.
How do I estimate the overall heat transfer coefficient U if I don't have test data?+
Use published reference ranges for the specific fluid combination and exchanger type as a starting estimate, such as the typical values table on this page, then refine with the manufacturer's design data or a detailed film-coefficient calculation once the exchanger type and materials are selected — U varies too widely by application for one universal number.
Can this calculator handle a condenser or an evaporator?+
Not directly — this calculator's duty formula covers sensible heat only (temperature change with no phase change). Condensing or boiling duty depends on latent heat and the mass flow undergoing the phase change, which is a different calculation, though the LMTD and area relationship can still apply once that duty is known separately.
Why did the calculator show an error about a temperature cross?+
A temperature cross happens when the hot fluid temperature drops below the cold fluid temperature at one end of the exchanger for the arrangement you selected, which makes the LMTD calculation mathematically invalid. This usually means the flow arrangement should be counter-current instead of parallel, or that the entered temperatures need rechecking.
Does this area result already include a fouling allowance?+
No — the area result uses the U value you enter directly. If that U value is a clean-surface figure, the calculated area will be a clean-condition minimum; add a fouling factor to U (reducing it) if you want the result to reflect long-term fouled operation, which a full thermal design would normally include.
Is the calculated area accurate enough for actually ordering an exchanger?+
Treat it as a first-pass sizing estimate only. A purchase-ready design needs the manufacturer's or a process engineer's detailed calculation, including fouling factors, a correction factor for the actual (often multi-pass) flow arrangement, pressure drop checks, and material and mechanical design per the applicable exchanger design code.
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