Pump Power Calculator
Calculate Smarter. Work Faster.
Hydraulic power, shaft power and motor input power for a pump — from flow rate, total head, pump efficiency and motor efficiency.
Flow, Head & Efficiency Inputs
Pump power, explained
Sizing a pump's drive motor starts with the hydraulic power — the actual useful work rate needed to lift a given flow of fluid against a given total head:
Pₕᵧᵨ = ρ × g × Q × H
where ρ is fluid density, g is gravitational acceleration (9.80665 m/s²), Q is volumetric flow rate, and H is total head — the total energy per unit weight of fluid the pump must add, expressed as an equivalent height, combining static lift, friction losses in the piping, and any pressure difference between the source and destination.
No pump converts 100% of the mechanical energy delivered to its shaft into useful hydraulic work — internal losses from fluid recirculation, disk friction, and mechanical (bearing/seal) friction mean the shaft power (also called brake power, the power the driver must deliver to the pump shaft) is always higher than the hydraulic power, by a factor set by the pump's efficiency:
Pₛₕₐᶠₜ = Pₕᵧᵨ / ηₚ
Finally, if the pump is driven by an electric motor, the motor itself also has losses (electrical and mechanical), so the motor input power — the actual electrical power drawn from the supply — is higher again than the shaft power, by the motor's own efficiency:
Pₘₒₜₒᵣ = Pₛₕₐᶠₜ / ηₘ
Pump efficiency itself is not a fixed number for a given pump — it varies across the pump's operating curve, peaking at its Best Efficiency Point (BEP) and dropping off at flow rates well above or below that point. For motor sizing, the shaft power should be checked not just at the design duty point but across the pump's full expected operating range, since running far from BEP both wastes energy and can shorten pump life through increased vibration and bearing/seal wear.
Worked Example
A centrifugal pump moves 50 m³/hr of water against 30 m total head, at 70% pump efficiency, driven by a motor with 92% efficiency.
- Q = 50/3600 = 0.01389 m³/s
- Hydraulic power = 1000 × 9.80665 × 0.01389 × 30 = 4,086 W ≈ 4.09 kW
- Shaft power = 4.09 / 0.70 = 5.84 kW (≈ 7.84 HP)
- Motor input power = 5.84 / 0.92 = 6.35 kW (≈ 8.52 HP)
A standard motor frame at or just above 6.35 kW (commonly a 7.5 kW / 10 HP motor in typical standard sizing steps) would normally be selected, giving headroom above the calculated duty point.
This calculator gives steady-state power at the design flow and head; actual motor selection should also check the pump's power curve across its full operating range (including any run-out condition) and apply the motor manufacturer's standard frame sizing.
Typical centrifugal pump efficiency by flow rate
| Pump size / flow range | Typical peak (BEP) efficiency |
|---|---|
| Small pumps, below ~10 m³/hr | 40 – 55% |
| Medium pumps, ~10–100 m³/hr | 55 – 75% |
| Large pumps, above ~100 m³/hr | 75 – 88% |
Efficiency generally rises with pump size because mechanical and disk-friction losses become a smaller fraction of total power handled as the pump gets larger — this is one reason a single large pump is often more energy-efficient than several smaller pumps doing the same combined duty, all else being equal.
Common mistakes when calculating pump power
1. Using static lift alone as "head" and ignoring friction losses. Total head is the static lift plus all friction losses in the suction and discharge piping (and any pressure head difference) — using static lift alone significantly understates the true head the pump must overcome, and therefore understates power.
2. Sizing the motor to shaft power at the design point only. Centrifugal pump power typically increases toward the low-head, high-flow end of its curve — a motor sized exactly to the design-point shaft power can be overloaded if the system operates further right on the curve (e.g. during low static head conditions).
3. Forgetting motor efficiency when comparing to motor nameplate ratings. Shaft power is not the same as motor input (electrical) power — comparing a calculated shaft power directly against a motor's kW nameplate without accounting for motor efficiency slightly understates actual electricity draw.
4. Using a generic efficiency figure instead of the actual pump curve. Pump efficiency varies with flow rate across the pump's operating curve and is different for every pump model and impeller trim — a rule-of-thumb efficiency is fine for early estimating, but final sizing should use the specific pump's published performance curve.
5. Mixing up density for non-water fluids. Pumping a fluid denser or lighter than water (brine, oil, slurry) changes hydraulic power proportionally — using water's density (1000 kg/m³) for a different fluid gives a power figure that's wrong by the same ratio as the density difference.
6. Not adding a safety margin on the selected motor size. Even after correctly calculating motor input power, it's common practice to select the next standard motor frame size above the calculated requirement, rather than the exact calculated value, to allow for pump wear, minor system changes, and starting torque requirements.
Frequently Asked Questions
Straight answers on hydraulic power, shaft power, and sizing the drive motor.
What is the formula for pump hydraulic power?+
Hydraulic power equals fluid density times gravitational acceleration times flow rate times total head, P = rho g Q H. This is the theoretical minimum power needed to move that flow against that head, with no allowance for pump or motor losses.
What is the difference between hydraulic power, shaft power, and motor input power?+
Hydraulic power is the useful work delivered to the fluid. Shaft power is what the pump's driver must supply to its shaft, which is higher than hydraulic power because the pump itself has internal losses (its efficiency). Motor input power is the electrical power drawn from the supply, which is higher again than shaft power because the motor also has its own efficiency losses.
What is total head and how is it different from just the vertical lift?+
Total head includes the static lift (the actual height difference the fluid is raised), plus friction losses in the suction and discharge piping, fittings and valves, plus any difference in pressure head between the source and the destination. It is always equal to or greater than the static lift alone, and using static lift alone will understate the power required.
Why does pump efficiency vary instead of being one fixed number?+
Every pump has a performance curve where efficiency changes with flow rate, peaking at its Best Efficiency Point (BEP) and falling off as flow moves away from that point in either direction. The efficiency figure used in a power calculation should reflect the actual expected operating flow rate, not just the pump's single best rated efficiency.
How much margin should I add when selecting the actual motor size?+
A common practice is to select the next standard motor frame size above the calculated motor input power requirement, rather than an exact custom size, which provides headroom for pump wear, minor system changes, and starting conditions. The specific margin depends on company standards and the criticality of the application.
Does fluid viscosity affect pump power, not just density?+
Yes — this calculator's formula assumes a water-like, low-viscosity fluid. For significantly more viscous fluids (like heavy oils), both the pump's head-flow performance and its efficiency are affected by viscosity, requiring viscosity correction factors from the pump manufacturer rather than the plain hydraulic power formula alone.
Why is my calculated motor input power lower than the motor's actual measured electrical draw?+
Several factors can explain a gap: the pump may be operating away from its assumed efficiency point on its curve, actual system head may differ from the design head, motor efficiency at partial load differs from its full-load rated efficiency, and there may be additional losses in the drive (like a belt or gearbox) not captured in a direct-coupled calculation.
Should I use the pump's efficiency at the design flow rate or its maximum (BEP) efficiency?+
Use the efficiency at the actual flow rate the pump will operate at most of the time, which is not always the same as its maximum BEP efficiency. If the pump's real operating point is away from BEP, using the peak efficiency figure will understate the true shaft power required at that operating point.
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